August 6, 2009
Here is code.
var foo = {
first: function () {
console.log("I am first");
},
second: function () {
console.log("I am second");
},
};
foo.first();
foo.second();
Everything works fine.
Now there is a need for function second to call function first. Try this and
it will fail.
var foo = {
first: function () {
console.log("I am first");
},
second: function () {
console.log("I am second");
first();
},
};
foo.second();
One way to fix this problem is to hardcode value foo inside the second
function. Following code works.
var foo = {
first: function () {
console.log("I am first");
},
second: function () {
console.log("I am second");
foo.first();
},
};
foo.second();
Above code works but hardcoding the value of foo inside the object literal is
not good. A better way would be to replace the hardcoded name with this .
var foo = {
first: function () {
console.log("I am first");
},
second: function () {
console.log("I am second");
this.first();
},
};
foo.second();
All is good.
Javascript allows one to create function inside a function. Now I am changing
the implementation of method second. Now this method would return another
function.
var foo = {
first: function () {
console.log("I am first");
},
second: function () {
return function () {
this.first();
};
},
};
foo.second()();
Also note that in order to invoke the returned function I have double ()() at
the end.
Above code does not work. It did not work because this has changed. Now this
in second function refers to the global object rather than referring to the
foo object.
Fix is simple. In the function second store the value of this in a temporary
variable and the inner function should use that temporary variable. This
solution will work because of Javascript's inherent support for closure.
var foo = {
first: function () {
console.log("I am first");
},
second: function () {
var self = this;
return function () {
self.first();
};
},
};
foo.second()();
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